0=-7x^2+14x+10

Solution for 0=-7x^2+14x+10 equation:

0=-7x^2+14x+10

We move all terms to the left:

0-(-7x^2+14x+10)=0

We add all the numbers together, and all the variables

-(-7x^2+14x+10)=0

We get rid of parentheses

7x^2-14x-10=0

a = 7; b = -14; c = -10;
Δ = b2-4ac
Δ = -142-4·7·(-10)
Δ = 476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{476}=\sqrt{4*119}=\sqrt{4}*\sqrt{119}=2\sqrt{119}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{119}}{2*7}=\frac{14-2\sqrt{119}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{119}}{2*7}=\frac{14+2\sqrt{119}}{14}
$